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(C) The initial capacitance of the air-filled parallel plate capacitor is given by $C = \frac{\epsilon_0 A}{d} = 9 \ pF$.When the space is filled with

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$81$

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(C) The initial capacitance of the air-filled parallel plate capacitor is given by $C = \frac{\epsilon_0 A}{d} = 9 \ pF$.When the space is filled with two dielectrics of thicknesses $d_1 = \frac{d}{3}$ and $d_2 = \frac{2d}{3}$,they act as two capacitors in series.The capacitance of the first part is $C_1 = \frac{K_1 \epsilon_0 A}{d_1} = \frac{6 \epsilon_0 A}{d/3} = 18 \left(\frac{\epsilon_0 A}{d}ight) = 18 	imes 9 = 162 \ pF$.The capacitance of the second part is $C_2 = \frac{K_2 \epsilon_0 A}{d_2} = \frac{12 \epsilon_0 A}{2d/3} = \frac{18 \epsilon_0 A}{d} = 18 	imes 9 = 162 \ pF$.The equivalent capacitance $C_{eq}$ for capacitors in series is given by $\frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2}$.$C_{eq} = \frac{C_1 C_2}{C_1 + C_2} = \frac{162 	imes 162}{162 + 162} = \frac{162}{2} = 81 \ pF$.

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